macfan55 Posted April 24, 2018 Share Posted April 24, 2018 How do I compose a job that only contains every 250-th record? I used the Sequential Numbering rule with the start number (76751) and there is no datafile involved. So for the total of 10.000 records I need only 40 records with 249 records skipped each time. On the same page is also a number printed from 1 to 40; but that is already working with a javascript-rule. Thanks for your help! Greetings from the Netherlands Quote Link to comment Share on other sites More sharing options...
Dan Korn Posted April 24, 2018 Share Posted April 24, 2018 In OnRecordStart: FusionPro.Composition.composeThisRecord = FusionPro.Composition.inputRecordNumber % 250 == 1; Quote Link to comment Share on other sites More sharing options...
macfan55 Posted April 25, 2018 Author Share Posted April 25, 2018 Thanks for the answer; worked flawless! Greetings from the Netherlands Quote Link to comment Share on other sites More sharing options...
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